Respuesta :

LammettHash
Assuming the square is not a typo, one can write


[tex]x^2+27=(x^{2/3})^3+3^3=(x^{2/3}+3)\bigg((x^{2/3})^2-3x^{2/3}+9\bigg)[/tex]

[tex]=(x^{2/3}+3)\bigg(x^{4/3}-3x^{2/3}+9\bigg)[/tex]

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