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30-05-2018
Mathematics

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Find the zeros of the function. write the smaller solution first, and the larger solution second. g(x)=-10x^2 +490g(x)=−10x 2 +490

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31-05-2018

[tex]g(x)=-10x^2+490\\\\-10x^2+490=0\ \ \ |+10x^2\\\\10x^2=490\ \ \ |:10\\\\x^2=49\to x=\pm\sqrt{49}\\\\\boxed{x=-7\ \vee\ x=7}[/tex]

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