Respuesta :

mathstudent55

m<AFB + m<BFC + m<CFD = m<AFD

m<AFB = m<CFD = 31; m<AFD = 90

31 + m<BFC + 31 = 90

m<BFC + 62 = 90

m<BFC = 28

m<CFE = m<CFD + m<DFE

m<DFE = m<BFC = 28

m<CFE = 31 + 28

m<CFE = 59

Answer: C. 59

ashley3512
28 because if angle afb is 31 and angle afc is equal to angle afb then angle bfc is 28 because 31+31 is 62 and 90-62=28. Angle cafe is equal to angle bfc so therefore it’s 28

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