Answer:
Distance traveled in 5 seconds = 47.75 meter.
Explanation:
We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this the velocity of body = 2.3 m/s, acceleration = 2.9 [tex]m/s^2[/tex], we need to calculate displacement when t = 5 seconds.
[tex]s= 2.3*5+\frac{1}{2} *2.9*5^2=47.75m[/tex]
So, distance traveled in 5 seconds = 47.75 meter.
