Answer: D) 209 Joules
Explanation:
Using the equation below:
[tex]Q= m\times c\times \Delta T[/tex]
Q= heat gained
m= mass of the substance = 10.0 g
[tex]\Delta T[/tex] = change in temperature =[tex](30-25)^0C=5^0C[/tex]
c = heat capacity of water = 4.186 J/g ° C
Putting in all the values we get:
[tex]Q=10g\times 4.186J/g^0C\times 5^0C[/tex]
[tex]Q=209Joules[/tex]
Thus heat gained by 10 g of water is 209 Joules
