Respuesta :

Answer:

(b) t-4 and t not equal 8

Step-by-step explanation:

[tex]\frac{t^2-4t-32}{t-8}=\frac{(t+4)(t-8)}{t-8}=t+4\,\,\mbox{with}\,\,\,\,\,t-8\neq0\implies t\neq 8[/tex]