Take stoichiometry In to consideration. The ratio of CaCO3 to CaCl2 is 1:1
Therefore the amount of moles in CaCO3 is same as moles in CaCl2.
Calculate the moles of CaCO3 using the equation n =m/M where
n = moles
m = mass
M =molar mass
And find the moles which is 0.208 mol in this case.
Therefore the moles of CaCl2 is also 0.208mol
(lol... Um doing all ur chemistry sums..)
