Respuesta :

Answer:

[tex]x^3+1[/tex]

Step-by-step explanation:

[tex] 26(x^3+1)^2-22(x^3+1)-3=0 [/tex]

Comparing to

[tex] A(u)^2+B(u)+C =0 [/tex]

Where A,B,C are constants

You should see that we need to substitute the [tex]x^3+1[/tex] with u.

Otras preguntas