Answer:
9.82×10⁻² m
Explanation:
w = Width of central maximum = 2.5 cm = 0.025 m
D = Distance between screen and slit = 2.2 m
λ = Wavelength of green light = 558 nm = 558×10⁻⁶ m
a = Width of slit
[tex]w=\frac{2\lambda D}{a}\\\Rightarrow a= \frac{2\lambda D}{w}\\\Rightarrow a= \frac{2\times 558\times 10^{-6}\times 2.2}{0.025}\\\Rightarrow a= 98208\times 10^{-6}= 9.82\times 10^{-2}\ m[/tex]
∴ Width of slit is 9.82×10⁻² m
