Answer:
The area of the gold foil is [tex]14.3 cm^{2}[/tex]
Explanation:
Mass of gold foil , m= 27.63 g
Thickness of gold foil , [tex]t=1000\mu m=0.1 cm[/tex]
Density of gold , [tex]\rho =19.32\frac{g}{cm^{3}}[/tex]
Let the area of gold foil be A then the total volume of gold foil is given by
[tex]V=At=\frac{m}{\rho }[/tex]
=>[tex]A=\frac{m}{t\rho }=\frac{27.63}{0.1\times 19.32} cm^{2}[/tex]
=>[tex]A=14.3 cm^{2}[/tex]
Thus the area of the gold foil is [tex]14.3 cm^{2}[/tex]
