Answer: The value of P(E∪F) = 0.64.
Step-by-step explanation:
Since we have given that
P(E) = 0.38
P(F) = 0.38
P(E∩F) = 0.12
So, we need to find the P(E∪F).
As we know the formula for the sets.
[tex]P(E\cup F)=P(E)+P(F)-P(E\cap F)\\\\P(E\cup F)=0.38+0.38-0.12=0.64\\\\P(E\cup F)=0.64[/tex]
Hence,the value of P(E∪F) = 0.64.
