Answer:
29 T/s
Explanation:
Given:
Area enclosed by loop, A = 1 m²
Maximum induced emf, e = 25.0 V
loop is oriented at an angle 30° with the x-y plane.
varying magnetic field is oriented parallel to z-axis.
we have to find [tex]\frac{dB}{dt}_{max}[/tex]
Induced emf is given by:
[tex] e =-A.cos\theta .\frac{dB}{dt}\\ \Rightarrow \frac{dB}{dt}=-\frac{e}{Acos\theta} = -\frac{25}{1\times cos30^o} = -28.86T/s[/tex]≈29T/s
