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Unpolarized light, with an intensity of I0, is incident on an ideal polarizer. A second ideal polarizer is immediately behind the first, and its axis of polarization is parallel to the first polarizer’s. How much of the light will be transmitted through the system?

Respuesta :

Answer:

Io/2

Explanation:

According to the law of Malus, the intensity of transmitted light after first polarizer is

[tex]I = I_{0}Cos^{2}\phi[/tex]

where, Ф be the angle between the axis of polarizer and analyser.

As teh mean value of Cos^Ф is 1/2, so the intensity of light transmitted from the first polarizer is

I = Io/2

Nnow it passes through another polaizer which is parallel to the first polaizer is same as I. It means the intensity of transmitted light is Io / 2 .

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