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A city currently has 31,000 residents and is adding new residents steadily at the rate of 1200 per year. If the proportion of residents that remain after t years is given by S(t) = 1/(t + 1), what is the population of the city 7 years from now? (Round your answer to the nearest whole number.)

Respuesta :

aramisdegaula1977

Answer:

Population = 1378.1994 residents

Step-by-step explanation:

The current population (t = 0) is 31,000 residents, the following year (t = 1), you have:

Population = 31000 (1 / (1 + 1)) +1200 = 16700

For the year t = 2

Population = 16700 (1 / (2 + 1)) +1200 = 5375

For the year t = 3

Population = 5375 (1 / (3 + 1)) +1200 = 2275. Successively it is found that for t = 7

Population = 1425,595 (1 / (7 + 1)) +1200 = 1378.1994

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