Answer:
120 m/s^2
(a) 6000 m
(b) 1200 m/s
Explanation:
mass, m = 10 kg
initial velocity, u = 0
Force, F = 1200 N
time, t = 10 s
Let a be the acceleration of the block.
By use of Newton,s second law
Force = mass x acceleration
1200 = 10 x a
a = 120 m/s^2
(a) Let the block travels by a distance s.
Use second equation of motion
[tex]s=ut+\frac{1}{2}at^{2}[/tex]
s = 0 + 0.5 x 120 x 10 x 10
s = 6000 m
(b) Let v be the final velocity of the block
Use first equation of motion
v = u + at
v = 0 + 120 x 10
v = 1200 m/s
