Answer:
[tex]2.17 m/s^2[/tex]
Explanation:
The car accelerates at a constant rate during the first 6 seconds of the trip, so we can calculate its acceleration by using the equation:
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final velocity
u is the initial velocity
t is the time
For the first 6 seconds of the trip, we have: (from the graph)
v = 27 m/s
u = 14 m/s
t = 6 s
Substituting into the equation, we find:
[tex]a=\frac{27-14}{6}=2.17 m/s^2[/tex]
