Given : 11x – 6y = –1; x = 8

Prove: start fraction 89 over 6 end fraction = y

11x – 6y = –1; x = 8

88 – 6y = –1

–6y = –89

y = start fraction 89 over 6 end fraction

A. a. Given; b. Symmetric Property of Equality; c. Subtraction Property of Equality; d. Division Property of Equality; e. Reflexive Property of Equality

B. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Symmetric Property of Equality

C. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Reflexive Property of Equality

D. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Addition Property of Equality; e. Symmetric Property of Equality

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slicergiza slicergiza · Answer 1 · 2019-10-29T08:10:11+01:00

Answer:

B. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Symmetric Property of Equality

Step-by-step explanation:

Given expression,

[tex]11x - 6y = -1; x = 8[/tex]

By substituting x = 8,

[tex]11(8) - 6y = -1[/tex]

[tex]88 - 6y =-1[/tex]

By subtraction property of equality,

[tex]-6y = -89[/tex]

Division property of equality,

[tex]y = \frac{89}{6}[/tex]

By symmetric property of equality,

[tex]\frac{89}{6} = y[/tex]