Answer:
Explanation:
I will show my thinking using words and numbers.
The fact that when the camels walked in rows of 2 one walked alone means tha the number of camels divided by 2 leaves a remainder of 1. Also, that means that if you subtract 1 from the number of camels, the new number is a multiple of 2. This is:
With the same reasoning, you obtain:
Now, the numbers of camels less 1 is a multiple of 2, 3, 4, and 5. Now, let's search the first (least) common multiple of 2, 3, 4, and 5.
For that, you have to factor each number into its prime factors:
The least common multiple is the product of the common and uncommon factors, each raised to its highest power: 2² × 3 × 5 = 60.
Remember that 60 is the number of camels less 1, thus the number of camels is 60 + 1 = 61.
The next common multiple is 2 × 60 = 120, which exceeds 100 thus the only possible value is the one determined above.
Now you can prove that 61 meets the conditions: