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29-05-2016
Mathematics

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Simplify. 5x^3/(7x^3+x^4)
5/7+x; where x is not equal to 0, -7
5/7+x; where x is not equal to -7
5/7x; where x is not equal to 0
5/7

Respuesta :

29-05-2016

Hello,

[tex] \frac{5 x^{3} }{7 x^{3} + x^{4} } = \frac{5 x^{3} }{x^{3}(7+x) }=\frac{5} {7+x} [/tex]

Answer Almost A with parenthesis

5/(7+x)

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