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Design a full-wave bridge rectifier to supply 12V DC voltage to a resistive load of RL=3Ω at the output, assuming an AC supply with 60 Hz frequency with the following characteristics: a) Unfiltered (without output capacitor) b) Filtered. Design a filter capacitor so that the ripple factor of the output voltage is less than %5. (You should revise the AC supply Vm calculated in (a) to match the 12V requirement.)

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Answer:

[tex]V_m= 18.85V[/tex] and c= 1.336mF

Explanation:

a) Unfiltered

We calculate the Voltage through the equation:

[tex]V_0=\frac{2V_m}{\pi}\\12=\frac{2V_m}{\pi}\\V_m= 6\pi V\\V_m= 18.85V[/tex]

So,

[tex]V_{in} = 18.85 sin wt\\ w=377Rad/s[/tex]

b) Filtered

We need to use the ripple factor,

[tex]rf=\frac{1}{4/sqrt{3}fRc}[/tex]

Solving and clearing for c,

[tex]c=\frac{1}{4\sqrt{3}fR*0.6}=1.336mF[/tex]

*Note that was given 5% of output voltage

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