Respuesta :

Answer:

x=2+i, x=2-i

Step-by-step explanation:

x^2-4x+5=0

Apply the quadratic formula.

There are are no real solutions for this equation.

What is a quadratic equation?

An equation whose highest degree is 2, is called a quadratic equation.

How to solve a quadratic equation?

We can solve a quadratic equation by two ways:

  • Factorization- If the quadratic expression is factorizable then we can factorize it and equate it to 0. Then we can apply the concept that when product of two or more expressions is 0 then at least one of the expression or both must be 0
  • By Shreedhar Acharya formula- A quadratic equation of the [tex]ax^{2} +bx+c=0[/tex] form  can be solved by the formula given below:

                          [tex]x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}[/tex]

                             or

                           [tex]x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}[/tex]

  • This [tex]\sqrt{b^{2}-4ac }[/tex] is called discriminant.
  • If the discriminant is negative, then the equation have no real solution.

How to find the solutions of x²-4x+5=0?

Comparing with the standard equation [tex]ax^{2} +bx+c=0[/tex],

  • a = 1
  • b = -4
  • c = 5

How to check the discriminant?

∴ Discriminant = [tex]\sqrt{b^{2}-4ac }[/tex] = [tex]\sqrt{-4}[/tex]

  • Here, the discriminant is negative, so there are no real solutions.
  • There are imaginary solutions.

Find out more about 'Quadratic Equation' here:  brainly.com/question/1214333

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