Answer:
Hence lowest (nonzero) frequency that gives destructive interference in this case = 3400 Hz
Explanation:
Since, the two are in out of phase,
their path difference is
d= nλ
[tex]d_2-d_1= n\lambda[/tex]
Given d1= 2.75 m
D= 3.90 m
[tex]d_2= \sqrt{D^2- d_1^2}[/tex]
[tex]d_2= \sqrt{3.90^2- 2.75^2}[/tex]
d_2= 2.76 m
2.76-2.75= 1×λ
λ= 0.01 m
0.01= 1*λ
λ =0.01
frequency ν = v/λ = 340/0.01
f= 3400 Hz
Hence lowest (nonzero) frequency that gives destructive interference in this case = 3400 Hz
