Respuesta :
Answer:
Depending on how the input of each function defined,
- The first choice [tex]\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace[/tex],
- The third choice [tex]\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace[/tex]
- The fourth choice [tex]\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace[/tex]
might be functions.
Step-by-step explanation:
A function between two sets (domain and range) should
- be defined for all elements in the domain, and
- map each element from the domain to exactly one element in the range.
The second choice can't be a function since the element [tex]a[/tex] from the domain is mapped to more than one element in the range.
Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be [tex]\lbrace a,\, 6, \, C\rbrace[/tex]. Similarly, the domain for the third and fourth relations should be [tex]\lbrace 1,\, 2, \, 3\rbrace[/tex] and [tex]\lbrace a,\, b, \, c\rbrace[/tex]