Respuesta :

Ashraf82

The differential for P = 0.2x² -17x -10 is P' = 0.4x - 17

Step-by-step explanation:

Let us revise how to differentiate an equation with respect to x

If the equation is [tex]y = ax^{n}+b[/tex] , where a , b are constant

  • The differentiation of the term [tex]ax^{n}[/tex] is [tex]a(n)x^{(n-1)}[/tex] (multiply the coefficient of x by the power"n" and subtract 1 from the power)
  • The differentiation of the term b is 0, because b is a constant
  • The differentiation of y is [tex]\frac{dy}{dx}=a(n)x^{(n-1)}+0=a(n)x^{(n-1)}[/tex]
  • You can write [tex]\frac{dy}{dx}[/tex] as y'

∵ P = 0.2x² - 17x - 10

- Let us differentiate each term

∵ The differentiation of 0.2x² is [tex]0.2(2)x^{2-1}=0.4x^{1}=0.4x[/tex]

∵ The differentiation of -17x is [tex]-17(1)x^{1-1}=-17x^{0}=-17(1)=-17[/tex]

∵ The differentiation of -10 is zero because the differentiation

    of the numerical term is 0

∴ The differentiation of P is P' = 0.4x - 17

The differential for P = 0.2x² -17x -10 is P' = 0.4x - 17

Learn more:

You can learn more about the differentiation in brainly.com/question/4279146

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