Answer:
v=15.24 m/s
Explanation:
Given that
Mass ,m= 1600 kg
radius ,r= 28 m
Coefficient of friction ,μ = 0.83
The radial force on the car when it takes turn
[tex]F=\dfrac{mv^2}{r}[/tex]
The friction force on the car
Fr= μ m g
The condition for motion without losing traction
F= Fr
[tex]\dfrac{mv^2}{r}=\mu\ m g[/tex]
v²=μ r g
[tex]v=\sqrt{\mu\ r g}[/tex]
Now by putting the values
[tex]v=\sqrt{0.83\times 28\times 10}\ m/s[/tex] ( take g=10m/s²)
v=15.24 m/s
The speed of the car will be 15.24 m/s
