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You are driving a 4000 kg pickup truck on a cold winter day when the coefficient of static friction for tires on the icy road is only 0.13. What is fastest you can drive around a bend whose radius of curvature is 50 m?

Respuesta :

Answer:

8 m/s

Explanation:

[tex]m[/tex] = mass of the pickup truck = 4000 kg

[tex]\mu_{s}[/tex] = Coefficient of static friction between tires and ice road = 0.13

[tex]r[/tex] = Radius of curvature = 50 m

The frictional force between tires and ice road provides the necessary centripetal force to move in circle. hence

centripetal force = frictional force

[tex]\frac{mv^{2}}{r} = \mu_{s} mg\\\frac{v^{2}}{r} = \mu_{s} g\\\frac{v^{2}}{50} = (0.13) (9.8)\\v^{2} = (0.13) (9.8) (50)\\v = 8 ms^{-1}[/tex]

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