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The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?

Respuesta :

Answer:

[tex]g'=\frac{g__R}{4}[/tex]

Explanation:

Given:

  • gravitational field strength of moon at a distance R from its center, [tex]g__R [/tex]
  • Distance of the satellite from the center of the moon, [tex]h=2R[/tex]

Now as we know that the value of gravity of any heavenly body is at height h is given as:

[tex]g'=g__{R}} \times \frac{R^2}{(2R)^2}[/tex]

[tex]g'=\frac{g__R}{4}[/tex]

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.

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