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The Boeing 737-800 aircraft can accelerate from rest to a takeoff speed of 300 km hr-1
in 25 seconds Calculate in ms-2 the value of this acceleration, assuming it to be constant.​

Respuesta :

MathPhys

Answer:

3.33 m/s²

Explanation:

If the acceleration is constant, it is equal to the average acceleration:

a = Δv / Δt

First, convert km/hr to m/s:

300 km/hr × (1 hr / 3600 s) × (1000 m/km) = 83.33 m/s

a = (83.33 m/s − 0 m/s) / 25 s

a = 3.33 m/s²

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