Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II) to insoluble Fe(III):

4Fe(OH)+(aq) + 4OH−(aq) + O2​(g) + 2H2​O(l) ------> 4Fe(OH)​3(s)

How many grams of O2 are consumed to precipitate all of the iron in 65.0 mL of 0.0550 M Fe(II)?