Answer:
15.05 * 10^23 atoms are present in 2.50moles of Al2(SO4)3
Explanation:
To solve this question, the Avogadro equation is used.
Number of moles (n) = number of atoms (N) / Avogadro number.
n = N / 6.02*10^23
So therefore;
2.50moles = N / 6.02* 10^23
N = 6.02* 10^23 * 2.50
N = 15.05* 10^23 atoms.
