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For the neutralization reaction: 2 HCl + Ca(OH)2 -> CaCl2 + 2H20, how many
grams of Ca(OH)2 are required to produce 135 grams CaCl2? The reaction
occurs in the presence of excess HCL.
60.29
9049
1359
180 g
Submit
Law of Conservation of Matter

Respuesta :

Eduard22sly

Answer:

90g of Ca(OH)2

Explanation:

2HCl + Ca(OH)2 —> CaCl2 + 2H20

Molar Mass of Ca(OH)2 = 40 + 2( 16 + 1) = 40 + 2(17) = 40 + 34 = 74g/mol

Molar Mass of CaCl2 = 40 + (2 x 3.5) = 40 + 71 = 111g/mol

From the equation,

74g of Ca(OH)2 produced 111g of CaCl2.

Therefore, Xg of Ca(OH)2 will produce 135g of CaCl2 i.e

Xg of Ca(OH)2 = (74 x 135) / 111 = 90g.

Therefore, 90g of Ca(OH)2 are required to produce 135g of CaCl2

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