Answer:
[tex]\frac{12 {z}^{ 3} {y}^{2} }{5 {x}^{ 2} } [/tex]
Step-by-step explanation:
We want to simplify:
[tex] \frac{36 {x}^{ - 2} {y}^{2} }{15 {z}^{ - 3} } [/tex]
The trick is that when a negative index in the numerator comes to the denominator , it becomes positive.
The vice-versa is also true.
That is:
[tex] {a}^{ - n} = \frac{1}{ {a}^{ n} } [/tex]
and
[tex] {a}^{n} = \frac{1}{ {a}^{ - n} } [/tex]
We simplify to get:
[tex]\frac{12 {z}^{ 3} {y}^{2} }{5 {x}^{ 2} } [/tex]
The last choice is correct.
