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Hemophilia and colorblindness are both X-linked, recessive traits. A hemophiliac woman marries a colorblind man. Assume that both are otherwise normal. If meiosis occurs normally for both parents, what phenotypes are possible among their offspring?

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Answer:

Normal daughters and Hemophiliac son

Explanation:

Females exhibit hemophilia and colorblindness in homozygous genotype only.  

The genotype of hemophiliac woman= X^hX^h

The genotype of colorblind man= X^cY

A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son

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Answer:

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