if 3.03 mol of ethane (C2H6) undergoes combustion according to the unbalanced equation
C2H6+O2 > CO2+ H2O
how many moles of O is required?

Respuesta :

Answer:

10.06 mol O₂

Explanation:

2C₂H₆ + 7O₂ => 4CO₂ + 6H₂O

Given 3.03 moles C₂H₆ combustion reaction requires 7/2(3.03 mol) O₂

= 10.06 mol O₂