Answer:
Translational kinetic energy of oxygen gas is 675 J
Explanation:
As we know that translational kinetic energy of ideal gas is given as
[tex]E = \frac{3}{2} nRT[/tex]
also by ideal gas equation we know that
[tex]PV = nRT[/tex]
so we have
[tex]E = \frac{3}{2}PV[/tex]
now we have
[tex]E = \frac{3}{2}(3 \times 10^5)(1.5 \times 10^{-3})[/tex]
so we have
[tex]E = 675 J[/tex]
