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If a gas in a closed container is pressurized from 14.9 atm to 16.5 atm and its original temperature was 33.1 °C, what would the final temperature of the gas be?

Respuesta :

olatunbosunadeoke

Answer: 339K

Explanation:

Initial pressure P1 = 14.9 atm

Final pressure P2 = 16.5 atm

Original temperature T1 = 33.1 °C

Convert Celsius to Kelvin

(33.1°C + 273 = 306.1K)

Final temperature T2 = ?

Apply the formula for Pressure's law

P1/T1.= P2/T2

14.9atm/306.1K = 16.5atm/ T2

To get T2, cross multiply

14.9 x T2 = 16.5 x 306.1

14.9T2 = 5050.65

T2 = (5050.65/14.9)

T2 = 339K

Thus, the final temperature of the gas would be 339K

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