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According to an​ article, 36​% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly selected​ adults, find the probability that the​ number, X, who have experienced a breakup at least once during the last 10 years is

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Step-by-step explanation:

The probability that an adult will experience breakup at least once during the last ten years is [tex]\frac{36}{100} = 0.36[/tex].

Hence, the probability that the adult will not experience breakup is (1 - 0.36) = 0.64.

As per the given question, X is the number of adults who face breakup. From the 9 people X persons can be chosen in [tex]^9C_X[/tex] ways.

The probability that X persons will experience breakup is [tex]^9C_X \times (0.36)^X \times (0.64)^{9 - X}[/tex].

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