Answer:
Probability = 0.4443
Step-by-step explanation:
The provided information is:
Consider X be the weight of extra-large egg that is normally distributed with mean [tex]\mu=3 \,oz[/tex] and standard deviation [tex]\sigma = 0.1 \,oz[/tex]
Also, sample size n = 12.
Thus, the probability that an egg in a carton of a dozen eggs weights more than 3.5 oz is:
[tex]\begin{aligned}P( X > 3.5) &= P(Z >\frac{3.5-3}{\frac{0.1}{\sqrt{12}}})\\&=P(Z>0.14)\\&=1-P(Z\leq0.14)\\&=1-0.557\\&=0.4443\end{aligned}[/tex]
