Answer:
The separation of the two slits is = 1.5 ×[tex]10^{-4}[/tex] m
Explanation:
Wave length [tex]\lambda[/tex] = 630 nm = 0.63 mm
x = 35 mm
l = 2.8 m
Order of fringes (m) = 3
We know that the separation of the two slits is given by
[tex]d = \frac{m \lambda \ l}{x}[/tex]
Put all the values in above formula we get
[tex]d = \frac{(0.63)(3)(2.8)}{(35)}[/tex]
d = 1.5 ×[tex]10^{-4}[/tex] m
Therefore the separation of the two slits is = 1.5 ×[tex]10^{-4}[/tex] m
