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The following thermochemical equation is for the reaction of methane(g) with water(g) to form hydrogen(g) and carbon monoxide(g). CH4(g) + H2O(g)3H2(g) + CO(g) H = 206 kJ When 4.20 grams of methane(g) react with excess water(g),______ kJ of energy are___________.

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Answer:

54.075KJ

Explanation:

Since methane is the limiting reactant.

From the reaction equation,

16 g of methane absorbs 206 KJ of energy

4.20 g of methane will absorb 4.20 × 206/16 = 54.075KJ of energy was absorbed.

From the equation, the value of the enthalpy of reaction is positive, this means that energy is absorbed in the reaction of methane and water. Hence the answer.

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