Question: The question is incomplete. The spectrum was not added to the question. Find attached of the spectrum
Answer:
(A)
(i) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
(ii) Calcium
(B) Wavelength = 2.03*10^-7 m
Explanation:
A)
(i) from the spectrum, the electron configuration can be written as;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
(ii) from the electron configuration, the element has 20 number of electron.
Therefore, the element is calcium.
(b)Calculating the wavelength using he formula;
λ = h*c/ΔE
where;
h = 6.626*10^-34
c = 3*10^8
ΔE = 0.980*10^-18
Substituting , we have;
λ = h*c/ΔE
= (6.626*10^-34 * 3*10^8)/ 0.980*10^-18
= 1.9878*10^-25/0.980*10^-18
= 2.03*10^-7 m
