Answer : The moles of [tex]NH_3[/tex] formed are, 22.3 moles.
Explanation : Given,
Moles of [tex]N_2H_4[/tex] = 16.72 mol
The given chemical reaction is:
[tex]3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)[/tex]
From the balanced chemical reaction, we conclude that:
As, 3 moles of [tex]N_2H_4[/tex] react to give 4 moles of [tex]NH_3[/tex]
So, 16.72 moles of [tex]N_2H_4[/tex] react to give [tex]\frac{4}{3}\times 16.72=22.3[/tex] moles of [tex]NH_3[/tex]
Therefore, the moles of [tex]NH_3[/tex] formed are, 22.3 moles.
