Answer: Required expression : [tex](n-1)+n+(n+1)=84[/tex]
Smallest number = 27
Step-by-step explanation:
Let the three consecutive number be n-1 , n , n+1 .
Since , the sum of three consecutive numbers is 84.
[tex]\Rightarrow\ (n-1)+n+(n+1)=84[/tex]
Remove parenthesis
[tex]n-1+n+n+1=84[/tex]
Simplify
[tex]3n=84[/tex]
Divide both sides by 3, we get
[tex]n=28[/tex]
That means the three consecutive numbers would be (28-1) , 28 , (28+1)
i.e. 27 , 28 , 29.
Hence, the smallest number is 27.
