27-05-2020
Chemistry

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A student dissolves 10.0 g of sodium sulfate (Na2SO4) in 250.0 mL of water.Calculate the molarity of the solution.

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27-05-2020

Answer:

0.281 M

Explanation:

M(Na2SO4) = 2*23.0 + 32.1 + 4*16.0 = 142.1 g/mol

10.0 g* 1 mol/ 142.1 g= (10/142.1) mol

250.0 mL = 0.2500 L

(10/142.1) mol/0.2500 L =0.281 mol/L = 0.281 M

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