The voltage across a charged capacitor measured in Volts is given by V(t) = 4(2.72)^{\frac{-t}{2} } where t is measured in seconds since the current was removed. Include at least three decimal places in all your answers.
a. What is the voltage after 2 seconds?
b. What is the 1-second growth factor?
c. When will the voltage be 1 Volt?
d. When will the voltage be x Volts? (Your answer should be an exact expression with x in it)
So first you plug 2 in for t 4(2.72)^(-2/2) 4/2.72 (because the simplified exponent is -1) divide and that's your answer.
Next you plug 1 in for t 4(2.72)^(-1/2) 4/sqrt(2.72) (because -1/2 as an exponent is 1/sqrt(x)) plug that into a calculator and that's your answer
For c, you plug 1 in for V(t). 1=4(2.72)^(-t/2) 1/4=2.72^(-t/2) Here is where I get stuck because I haven't done logarithms in a year and forget how to do them but I know that's what you have to do for this problem.
In the last problem you plug x in for V(t) and I'd assume go about solving it the same as c. Sorry I couldn't be of more help.
