baikens674 baikens674
  • 27-08-2020
  • Mathematics
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3ab - 2bc = 12 solve for b

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slee04 slee04
  • 27-08-2020
(3ab/b)-(2bc/b)=12/b
3a-2c=12b^-1
(3a-2c)/12=(12b^-1)/12
(3a-2c)/12=b^-1
12/(3a-2c)=b
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