josh734853 josh734853

30-09-2020
Mathematics

contestada

x+3y−z=2
4x+2y+5z=1
3x+z=12

Respuesta :

mhanifa mhanifa

30-09-2020

Answer:

x=5, y= -2, z= -3

Step-by-step explanation:

Given system of equations

x+3y−z=2 (1)
4x+2y+5z=1 (2)
3x+z=12 (3)

Solution

3*(2) - 2*(1)

10x + 17z = -1 (4)

17*(3) - (4)

51x - 10x + 17z - 17z = 12*17 - (-1)
41x = 205
x = 5
5*3 + z = 12 ⇒ z = -3
5 + 3y -(-3) = 2 ⇒ 3y = -6 ⇒ y = -2

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