Answer:
[tex]10 \sqrt{3} [/tex]
Step-by-step explanation:
[tex] \sqrt{48} + \sqrt{108} \: \: in \: \: \: form \: \: of \: \: k \sqrt{6} \\ \sqrt{48} + \sqrt{108} = \sqrt{(4 \times 4 \times 3)} + \sqrt{(9 \times 3 \times 4)} = \\ 4 \sqrt{3} + 6 \sqrt{3} = 10 \sqrt{3} [/tex]
