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The position vector r of a particle relative to a certain point has a magnitude of 3m , and the force F on the particle has a magnitude of 4N . What is the angle between the directions of r and F if the magnitude of the associated torque equals

Respuesta :

Answer:

θ = 0

Explanation:

As per the question Given that

Magnitude = 2m

Force F contains MAgnitude = 4N

Based on the above information

T = rFsinθ

Now if

T = 0,

so r and F would not be zero so that sinθ  should be equivalent to zero for holding an equation

Therefore

θ = 0

The same is to be considered as it is relevant as per the question