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An object, initially traveling at a velocity of 52 m/s, experiences an acceleration of -9.8 m/s². How much time will it take it to come to rest? *

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MathPhys

Answer:

5.3 s

Explanation:

Given:

v₀ = 52 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

0 m/s = (-9.8 m/s²) t + 52 m/s

t = 5.3 s

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